Starting from rest, a car accelerates at a rate of 10.7 m/s^2 for 12 seconds. what is its velocity at the end of this time?

Velocity of the car at the end of this time=128.4 m/s

Explanation:

initial velocity Vi=0

final velocity=V

acceleration= a=10.7 m/s²

time =t=12 s

using kinematic equation V= Vi + at

V=0+ 10.7 (12)

V=128.4 m/s

Thus the final velocity of the car =128.4 m/s

the total distance traveled by the car is

30km + 49km = 79 km .