A15.6 g sample of ethyl alcohol absorbs 0.207 kcal of energy as it is heated. if the initial temperature of the ethanol was 21.5 °c, what is the final temperature of the ethanol? (cethanol = 0.58 kcal/kg °c) 22.9 ° c 25.0 ° c 44.4 ° c

m = mass of sample = 15.6 g = 0.0156 kg

c = specific heat of the sample = 0.58 kcal/kgC = 580 cal/(kgC)

= initial temperature = 21.5 C

= final temperature = ?

Q = heat absorbed = 0.207 kcal = 207 cal

using the equation

Q = m c (-)

207 = (0.0156) (580) (-21.5)

= 44.4

explanation:

could i give you a exaplo that could you?

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