An object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction when its x-coordinate is 3.18 cm. if its x-coordinate 2.85 s later is −5.00 cm, what is its acceleration?

For this case we have the following equation:

Δx = ½ a (Δt) ² + vΔt

Where,

Δx: displacement

a: acceleration

Δt: total time

v: initial speed

Clearing the acceleration we know:

a = 2 (Δx - vΔt) / (Δt) ²

We now perform the calculations.

The total time is:

Δt = 2.85 - 0 = 2.85

Δx = - 5 - 3.18 = - 8.18

v = 10

Substituting values we have:

a = 2 (-8.18 - (10) (2.85)) / (2.85) ²

a = -9.03 cm / s ^ 2

The acceleration of the object is:

a = -9.03 cm / s ^ 2:

the earths atmosphere is made up of nitrogen and oxygen. solids can turn into gasses through a process called sublimation. sublimation is the transition of a substance directly from the solid to the gas phase, without passing through the intermediate liquid phase.

hope this : d

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.