Physics, 16.07.2019 17:30 JorgeW5St

(a) when rebuilding her car's engine, a physics major must exert 300 n of force to insert a dry steel piston into a steel cylinder. what is the magnitude of the normal force between the piston and cylinder? (b) what is the magnitude of the force would she have to exert if the steel parts were oiled?

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Answer from: mraymundo025p0gpw9

A) The magnitude of the normal force between the piston and cylinder is : 1000 N

B) The magnitude of the force exerted when parts are oiled = 10000 N

Given data :

Force exerted by physics major = 300 n

coefficient of friction of dry steel cylinder ( μ ) = 0.3 ( found online )

coefficient of friction with oil in between ( μ ) = 0.03 ( found online )

A) Determine the magnitude of normal force

Force applied ( Fa ) = frictional force ( μ N )

therefore :

N = Fa / μ

where μ = 0.3

magnitude of normal force ( N ) = 300 / 0.3

= 1000 N

B) Determine the magnitude of force when oil is applied

N = Fa / μ

= 300 / 0.03

= 10000 N

Hence we can conclude that The magnitude of the normal force between the piston and cylinder is : 1000 N and The magnitude of the force exerted when parts are oiled = 10000 N

Learn more about magnitude of force : link

Answer from: zoeycrew

There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03

Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
$F_f = \mu N$
where $\mu$ is the coefficient of friction, while N is the normal force. So we have:
$F=\mu N$
since we know that F=300 N and $\mu=0.3$ , we can find N, the magnitude of the normal force:
$N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N$

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is $\mu=0.03$ due to the presence of the oil. Therefore, we have:
$N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N$

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