Aballoon has a volume of 10,500 liters, and the temperature is 15°c. if the temperature were -25°c, what would the volume of the balloon be? 12,194 l 9,042 l

According to Charle's law; the volume of a fixed mass of a gas is directly proportional to the absolute temperature at constant pressure.
VT= a constant
V1/T1 = V2/T2
V1 = 10,500 liters, T1= 15+273 =288 K; V2= ?, T2 = -25 +273 = 242 K
10,500/288 = V2/242
 V2 = (10,500 ×242)/288
      = 8822,92 Liters
 Therefore; the new volume of the balloon will be 8823 Liters

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