Abilliard ball moving at 6.00 m/s strikes a stationary ball of the same mass. after the collision, the first ball moves at 5.39 m/s at an angle of 26.0° with respect to the original line of motion. assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision.

The final velocity of the second billiard ball is 11.1 m/s.

The given parameters;

Apply the principle of conservation of linear momentum for elastic collision.

m₁u₁ + m₂u₂ = m₁v₁  + m₂v₂

Apply one dimensional velocity in x-direction;

Apply one dimensional velocity in y-direction

The resultant of the second ball final velocity is calculated as follows;

Thus, the final velocity of the second billiard ball is 11.1 m/s.

Learn more here:link

Explanation:

In the initial direction of motion we can use momentum conservation

so here we have

now by momentum conservation along perpendicular direction we can use as

So the magnitude of the final speed of the stuck ball is given as

direction of motion given as

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.