In a hydraulic garage lift, the small piston has a radius of 5.0 cm and the large piston has a radius of 15 cm. what force must be applied on the small piston in order to lift a car weighing 20,000 n on the large piston?

For Pascal's principle, the pressure exerted on the first piston is equal to the pressure exerted on the second piston:

which means

where F1, F2 are the two forces and A1, A2 the areas of the two pistons.

The areas of the pistons are:


And the force on the second piston is , so the force that should be applied on the first piston is

Is it b the answer and yes

The center is basically the heart of it