Use the graph below to answer the question that follows: what are the amplitude, period, and midline of the function? amplitude: 4; period: 2π; midline: y = −1 amplitude: 8; period: 2π; midline: y = 1 amplitude: 8; period: π; midline: y = −1 amplitude: 4; period: π; midline: y = 1

Amplitude : 4

Period: 2π

Mid-line: y=-1

A is correct

Step-by-step explanation:

We are given graph of periodic function.

We need to find amplitude, period and midline of the function.

From graph:

Maximum value  = 3

Minimum value = -5

The mid-line equation, y=-1

Amplitude: Distance between mid-line and maximum value

Amplitude = 3-(-1) = 4

The amplitude of given graph is 4

Period: It is time when graph repeat their path.

In the given graph repeat their in 2π of interval.

The period of graph is 2π

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

answer: yes i agree that you should not put it on/p>

step-by-step explanation: the reason for this is that it wastes other peoples time and also make them fail as well and that is never good.