Describe the steps you would use to factor 2x ^ 3 + 5x ^ 2 - 8x - 20 completely then state the factored form. this isn't multiple choice btw

2·x^3 + 5·x^2 - 8·x - 20 = 0

You see that the term will be 0 for x = 2

(2·x^3 + 5·x^2 - 8·x - 20) / (x - 2) = 2·x^2 + 9·x + 10 = 0

You can use the abc-formula to solve the quadratic equation.

x = -2.5 ∨ x = -2

So the factored form will be

2·x^3 + 5·x^2 - 8·x - 20 = 2·(x - 2)·(x + 2)·(x + 2.5)

one set of data has more variation than the other. hope this !

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: