Find the value of z /2 that corresponds to a confidence level of 89.48%.

Using confidence interval concepts, it is found that the critical value is

For a confidence level of , the critical value of z is z with a p-value of:

In this problem, confidence level of 89.48%, thus the p-value of the z-score is:

Looking at the z-table, this value is .

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Step-by-step explanation:

The given confidence level : c= 89.48%.

⇒ c= 0.8948   [ in decimal]

Then, the significance level =

Now, to find the value of , we need to find the two -tailed z-value using z-table for or we can also find the one-tailed z-value for  for

Using z-value table , the value is

Hence , that corresponds to a confidence level of 89.48%.

what do you need me to answer?

step-by-step explanation:

f is the midpoint of