Which set of ordered pairs could be generated by an exponential function? (0, 0), (1, 1), (2, 8), (3, 27) (0, 1), (1, 2), (2, 5), (3, 10) (0, 0), (1, 3), (2, 6), (3, 9) (0, 1), (1, 3), (2, 9), (3, 27)

For this case we must find the set of ordered pairs that form an exponential function.

When observing, the last set of ordered pairs is an exponential function of the form:

For x = 0:

We have the ordered pair:

For x = 1:

We have the ordered pair:

For x = 2:

We have the ordered pair:

For x = 3:

We have the ordered pair:

The set of ordered pairs that form an exponential function is:

step-by-step explanation:

given expression is .

now we need to simplify the given expression .

we know that square root is equivalent to the power 1/2. so that means we can take half of the exponents to get the square root of given expression.

expanding that will give a very very large number so let's keep answer in exponent form.