Mathematics, 21.07.2019 18:30 meganpaughstu

A3-lb force acting in the direction of the vector (3,-1) moves an object just over 9 ft from point (0,5) to (6,-2). find the work done to move the object to the nearest foot-pound

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Answer from: diamond2738

The Work done to move the object is $=23.15 \text { foot pounds }$

Step-by-step explanation:

Given;

Force F=3 l b s

Vectors of F= (3,-1)

Moves object to a distance=9 f t s

Let A and B be the displacements Vectors

A= (0,-5)

B= (6,-2)

To Find:

Work done in foot-pounds

Solution:

Work done $W=F \times D$

Direction of force vector= (3,-1) (i, j)

=3i-j

Unit of force vector $=\sqrt{3^{2}+\left(-1^{2}\right)}$

$=\sqrt{9+1}$

Force vector=(Force/Unit Vector)Direction of force vectors

F= $3 / \sqrt{10} \times(3 i-j)$

Direction of motion vector= (B-A)

= (6,-2)-(0,-5) x i,j)

=(6-0),(-2-5) x (i, j)

=(6,-7) x (i, j)

=6i-7j

Unit of motion vector $=\sqrt{6^{2}+\left(-7^{2}\right)}$

$=\sqrt{36+49}$

$=\sqrt{85}$

Motion Vector= (Distance moved by the object/Unit motion vector) × (Direction of motion vectors)

$D=9 / \sqrt{85} \times(6 i-7 j)$

Workdone $W=F \times D$

$= [3/ \sqrt{10} \times (3i-j)] \times [9/ \sqrt{85} \times (6i-7j)]$

$= [3/ \sqrt{10} \times 9/ \sqrt{85}] \times [(3i-j) \times(6i-7j)]$

$= [3/3.1623 \times 9/9.2195] \times [(3\times6) + ((-1) \times (-7))]$

$= [0.94867 \times 0.97619] \times [18+7]$

$=23.15 \text { foot pounds }$

Result:

Work done to move an object $=23.15 \text { foot pounds }$

Answer from: 1940swannabe

$W = 25.617\,lbf\cdot ft$

Step-by-step explanation:

The work done to move the object is:

$W = F \cdot s \cdot \cos \alpha$

The angle of the force with respect to change in the position vector is:

$\alpha = \tan^{-1}\left(-\frac{7}{6} \right) - \tan^{-1}\left(-\frac{1}{3} \right)$

$\alpha \approx 18.415^{\textdegree}$

The magnitude of the work done is:

$W = (3\,lbf)\cdot (9\,ft)\cdot \cos 18.415^{\textdegree}$

$W = 25.617\,lbf\cdot ft$

Answer from: Quest

Okay so for every triangle has three angles that always add up to 180 degrees. and to tell the difference between whether they are secure, right or obtuse is that acute: has one angle that is less than 90 degrees. right triangle means there is at least one angle that is exactly 90 degrees. and an obtuse angle has an angle that is bigger than 180 degrees. i’ll do #13 as an example: 13. 40 and 50 so if every triangle has 180 degrees 40+50= 90 degrees then180-90= 90 degrees so the third angle is 90 degrees and because this triangle has a 90 degree angle it means it is a right triangle

Answer from: Quest

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

I’m not sure how to solve these type of problems

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