Given a mean of 7.6 and a standard deviation of 3.1 what is the z-score of the value 10 rounded to the nearest tenth ? a)0.8 b)0.9 c)1.7 d)5.7

Choice A) 0.8



Work Shown:

mean = mu = 7.6
standard deviation = sigma = 3.1
x = 10 is the raw score

Use those values to find the z score
z = (x-mu)/sigma
z = (10-7.6)/3.1
z = 2.4/3.1
z = 0.7741935483871
z = 0.8 (approximate answer to the nearest tenth, ie one decimal place)