Marcus has a pool that can hold a maximum of 4500 gallons of water. the pool already contains 1500 gallons of water. marcus begins to add more water at a rate of 30 gallons per minute. write an inequality that shows the number of minutes, m, marcus can continue to add water to the pool without exceeding the maximum number of gallons.

Inequality is m ≤ 1000

Step-by-step explanation:

Capacity of the pool to hold the maximum water is = 4500 gallons of water.

Pool is already having 1500 gallons of water so remaining volume of the pool that can be filled is = 4500 - 1500 = 3000 gallons

Marcus begins to add 30 gallons water per minute and it takes "m" minutes to  fill the remaining volume.

So amount of water required = 30m gallons

There is a condition that Marcus continues to add water without exceeding the maximum amount of water.

This means remaining amount "3m gallons" will be never cross the limit of "3000 gallons" of remaining volume of water.

Now we can form the inequality as 3m ≤ 3000

or m ≤ 1000

Therefore, answer is m ≤ 1000

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

d

step-by-step explanation: