Find two consecutive even integers such that twice the smaller is 16 more than the larger

Define x:
Let one of the numbers be x.
The other number is x + 2

Construct equation:
twice the smaller is 16 more than the larger
⇒2x = x + 2 - 16

Solve x:
2x = x + 2 - 16
x = -14

Find the two numbers:
Smaller number = x = -14
Larger number = x + 2 = -12

The two numbers are -14 and -12

Let's make an equation. X will be the smaller number while y is the bigger.
x+2=y; since they're consecutive even numbers. We will use that equation to represent y.
Twice the smaller; 2x
16 more than the larger; 16+x+2
2x=16+x+2; let's add like terms.
2x=18+x
Let's subtract x from both sides.
x=18
If the smaller number is 18, the bigger number is 20.

The two numbers are 18 and 20.

put like terms together.orremember that the 45 becomes negative when moved to the other side.orthe minuses cancel out.

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.