Ncircle a shown below, m arc bc is 61° and m arc ef is 76°: points b, c, e, f lie on circle a. lines be and cf pass through point d creating angle edf. measure of arc bc is 61 degrees and what is m∠fde?

The correct answer is 68.5°

The calculated result of the angle FDE is 68.5°. Whenever two chords cut across a circle, the resulting angle is equivalent to half of the sum of the measurements of the arc the angle intersects and that which the angle vertical to the first angle intercepts.

m<FDE = 1/2( Arc BC + Arc 76)

m<FDE = 1/2 (61° + 76°)

m<FDE = 137/2 = 68.5°

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