Which polynomial function has a leading coefficient of 1, roots –3 and 8 with multiplicity 1, and root 4 with multiplicity 2? f(x) = 2(x + 3)(x + 4)(x – 3) f(x) = 2(x – 8)(x – 4)(x + 3) f(x) = (x + 8)(x + 4)(x + 4)(x – 3) f(x) = (x – 8)(x – 4)(x – 4)(x + 3)

f(x) = (x – 8)(x – 4)(x – 4)(x + 3)

Step-by-step explanation:

A polynomial function with roots has the following format:

In which a is the leading coefficient.

In this problem, we have that:

Leading coefficient 1, so

roots -3 and 8 with multiplicity 1, so .

root 4 with multiplicity 2, so

So the correct answer is:

f(x) = (x – 8)(x – 4)(x – 4)(x + 3)