Find the magnitude and direction angle for the vector v=6cos137degrees i+6sin137degrees j. a.) 6,137 degrees b.) 6,43 degrees c.)6squareroot of 2, 43 degrees d.) 6squareroot of 2, 137 degrees

The vector in its generic form is given by:
 v = lvl * (cos (theta) i + sin (theta) j)
 Where,
 lvl: magnitude of the vector
 theta: direction angle
 We have the following vector:
 v = 6cos137degrees i + 6sin137degrees j.
 Rewriting:
 v = 6 (cos137degrees i + sin137degrees j)
 Thus,
 lvl = 6
 theta = 137 degrees
 
 The magnitude and direction angle for the vector are:
 A.) 6,137 degrees

Omg that is a big question and weird words and i’m only 5

The first graph is the answer