Suppose that 68% of people own dogs. if you pick two people at random, what is the probability that they both own a dog?

Hola!

Given: 68% own dogs

→ 68% of the time the first person you pick will own a dog.

P (First person owns dogs) = 68/100 = 0.68

→ 67% of those 67% of the time the second person you pick will own a dog.

P (Second person owns dogs) = 68/100 = 0.68

Thus,

→ P (both owns dogs) = (0.68) × (0.68) = 0.4624

hope it helps!