Anita invested $6000, some at 5% and the rest at 6%. if the yearly income is $337.50, what is the amount invested at each rate?

Let the amount invested with 5% interest be x

Therefore, the amount invested with 6% interest will be (6000-x)

It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:

Multiplying both sides by 100 we get:

Subtracting both sides by 36000 we get:

Thus, the amount invested at 5% is $2250

Therefore, the amount invested at 6% will be $(6000-2250)=$3750

the answer is true.

step-by-step explanation: