The graphs of the equations y=2x+2 and y=-2x+a+1 intersect n quadrant 1 for which values of a? ○0 < a < 1○a < 1○a_> 1○a> 1

Solve the system of equations:
y=2x+2  (1)
y=-2x+a+1(2)
for x and y
(1)-(2)
4x-a+1=0 => x=(a-1)/4
(1)+(2)
2y=a+3 => y=(a+3)/2

x>0 if (a-1)/4>0 => a>1
y>0 if (a+3)/2>0 => a>-3

For both x & y >0, we have the condition a>1.

Note that if a=1, then the intersection poin lies ON the x-axis, and therefore NOT in quadrant 1.