In this figure triangle bae is congruent to triangle dea. which statement is true by cpctc?

∠BAF≅∠DEF

Step-by-step explanation:

In the given figure triangle BAE is congruent to triangle DEA i.e. ΔBAE ≅ ΔDEA.

We know that if two triangles are congruent then their corresponding angles are congruent.

Since,  ΔBAE ≅ ΔDEA, the  by CPCTC [congruent parts of congruent triangles are congruent]

∠BAE≅∠DEA

Since F is a point on AE

So, ∠BAE≅∠DEA

⇒ ∠BAF≅∠DEF

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

yes

step-by-step explanation: