Someone (06.01) if you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to x from the first equation is substituted into the second equation. x + 4y = −9 2x + 5y = −6 (6 points) 2x + 5(4y − 9) = −6 2x + 5(−4y − 9) = −6 2(4y − 9) + 5y = −6 2(−4y − 9) + 5y = −6 (06.03) how can one half x − 5 = one third x + 6 be set up as a system of equations? (6 points) a) 2y + x = −10 3y + x = 18 b)2y + 2x = −10 3y + 3x = 18 c) 2y − x = −10 3y − x = 18 d)2y − 2x = −10 3y − 3x = 18

(06.01)  ⇒ The answer is the listed number 4.

(06.03) ⇒ The answer is C

Step-by-step explanation:

Ok, for the (06.01) what we should do is clear the X so we can later on replace it.

(1)  x + 4y = -9

(2)   x = -9 -4y   (at this point we are moving the 4y to the other side of the equation and since its positive in one side, it goes to the other with a minus on it.)

(3) x = -4y - 9  (all we do here is rearrenge the factors on the right side)

Then we should replace the x in the second equation with (3)

(4)  2x + 5y = −6

(5)  2(−4y − 9) + 5y = −6

And we find the answer thats listed.

(06.03)

First we need to write the equation given.

(1)  

Now we work with each side for separate. Since both sides are equal to eachother we can make them equal to y to both sides.  And we get this two equations

(2)  

(3)  

We multiply (2) for 2 in both sides of the equation, to remove the fraction. And we will multiply (3) for 3 in both sides of the equation, to remove the fraction.

And we have this new system of equations.

(4)  2y = x - 10

(5)  3y = x + 18

Now we need to rearrenge the factors, and we will move the x  to the left side in both equations, and since both are positive, they pass with a minus sign on it.

So we get.

2y − x = −10

3y − x = 18

Thus the answer is C.

answer is:

1.75 pounds