Find a general term a(n) for the geometric sequence: a(3)=2, a(6)=1/4

a_n=arⁿ⁻¹

a_n nth term sequence

a= first term of the sequence

r= common ratio

a₃=ar²

2=ar²

a₆=ar⁵

1/4=ar⁶

a=2/r²

1/4=r⁶/r²

1/4=r⁴

r=1/(4)^(1/4)

a=1/r²=1/(1/(4)^(1/4))^(2)=1/1/2= 2

a_n=2{1/(4)^(1/4)}ⁿ⁻¹