The number of peanuts in a 16-ounce can of nut munchies is normally distributed with a mean of 96.3 and a standard deviation of 2.4 peanuts. the number of peanuts in a 20-ounce can of gone nuts is normally distributed with a mean of 112.6 and a standard deviation of 2.8 peanuts. ( a. carmen purchased a 16-ounce can of nut munchies and counted 100 peanuts. what is the z-score for this can of peanuts? ( b. angelo purchased a 20-ounce can of gone nuts and counted 116 peanuts. what is the z-score for this can of peanuts? ( c. carmen declares that purchasing her can of nut munchies with 100 peanuts is less likely than angelo purchasing a can of gone nuts with 116 peanuts. is carmen’s statement correct? use the definition of a z-score to support or refute carmen’s claim.

To calculate for the z-score we use the formula:
z=(x-μ)/σ
thus the answers to questions will be as follows:

a]Carmen purchased a 16-ounce can of Nut Munchies and counted 100 peanuts. What is the z-score for this can of peanuts?
x=100
μ=96.3
σ=2.4
z=(100-96.3)/2.4
z=1.542

b]Angelo purchased a 20-ounce can of Gone Nuts and counted 116 peanuts. What is the z-score for this can of peanuts?
x=116
μ=112.6
σ=2.8
thus
z=(116-112.6)/2.8
z=1.214

c]Carmen declares that purchasing her can of Nut Munchies with 100 peanuts is less likely than Angelo purchasing a can of Gone Nuts with 116 peanuts. Is Carmen’s statement correct? Use the definition of a z-score to support or refute Carmen’s claim.
This is very correct because because by definition of z-score, Munchies with 100 peanuts is 1.542 away from the mean as compared to Munchies with 116 peanuts which is 1.214 standard deviations from the mean hence the higher likelihood. 

A5 miles because when you look at the chart count how many times it goes into it i don’t even know wha,t i’m saying anymore mpbut long stor6 short it’s 5 miles