Write the standard form of the line that passes through the point (-2, 4) and is parallel to x - 2y = 6. type your answer in the box provided or use the upload option to submit your solution. explain how you got the answer

The line x - 2y = 6 we can find the slope of by solving for y

x - 2y = 6
-2y = -x + 6 --- subtract 6 from both sides
y = (-x + 6)/-2 --- divide both sides by -2
y = x/2 - 3

x/2 is equivalent to 1/2 * x.
this is in y = mx + b form where m is the slope, so the slope should be 1/2.

lines are parallel if their slopes are the same.
so the slope passing through
(-2, 4) should also have a slope of 1/2.

use point-slope form with (x1,y1) = (-2,4) and slope = 1/2

y - 4 = 1/2(x + 2)

standard form is Ax+By + C where A and B are not decimals.
put x and y together

y - 4 = 1/2x + 1
- 4 = 1/2x - y + 1 subtract y from both sides
- 5 = 1/2x - y subtract 1 from boths sides

multiply both sides by 2

-10 = x - 2y

so the standard form is x - 2y = -10.
also y u no reply to dms

Ithink you're supposed to multiply 12.50 which is how much he makes per hour and then multiply it by each number then add whats left togrther and there's your answer