Find the length of one side of a square inscribed in a circle that has a radius of 2cm

Since the square is inscribed in the circle, a diagonal
of the square is a diameter of the circle.

The diameter of the circle = 2 x radius = 4 cm .
The diagonal of the square = 4 cm.

The diagonal of a square is (length of a side) x (√2).

Side x √2 = 4 cm

Divide each side by √2:

Side = 4 cm / √2  =  4 √2 / 2  =  2 √2 =  2.83 cm  .

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

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