The sum of 4 consecutive multiples of 8 is 208. what is the largest number in the set?

X will be the smallest number in the set. Let's make an equation for the second smallest, third smallest, and largest.
x+8= second smallest
x+16= third smallest
x+24= biggest
Let's add them.
x+x+8+x+16+x+24=208; let's add like terms.
4x+48=208; let's subtract 48 from both sides.
4x=160; let's divide.
160÷4=40
This means the smallest number is 40. We can now check our answer.
40+48+56+64
88+120
208

So, the biggest number is 208.

X=14 hope it !