The side lengths of triangle abc are 3, 4, and 5. which set of ordered pairs form a triangle that is congruent to triangle abc? −3,−3,,5) ,−,,3) ,−,−,1) ,,,1)

The answer for this is A.)(-3,1) , (-3,5) , (0,5)

If you want to know whether triangles on a coordinate plane are congruent, you use the Distance Formula to find their side lengths. Now, since we already have the lengths of Triangle ABC (which is 3,4,5), what we only need to do is to find the lengths of the second triangle (let's name it Triangle DEF). 

With the use of Distance Formula -->  √(x2−x1)^2+(y2−y1)^2

Triangle DEF's vertices are: D(-3,1) ; E(-3,5) ; F(0,5)

Now, let's find its side lengths: 

DE = √(-3−(-3))^2+(5−1)^2 = 4
EF = √(0−(-3))^2+(5−5)^2 = 3
DF = √(0−(-3))^2+(5−1)^2 = 5

ΔABC≅ΔDEF

Hope this helps :)

40%=2/550=1/230=3/1056=14/25