Apple uses cheap labor in factories in china to manufacture its cell phones. the probability that a phone is defective is 0.02. what is the probability that a sample of 500 iphones will contain exactly 5 defective phones? a.) what is the average number of defective phones? (no decimals) b.) the probability of getting 5 defective phones? (to thousandths)

Let x be the random variable representing defective phone. Let n be the sample size. Let p be the probability that phone is defective.

Given: n=500, p= 0.02

From given information we know that x is random variable such that p is the probability of success and it is constant for each trial. Sample size n is fixed.

X follows Binomial distribution with parameters n=500 and p=0.02

a). The average number of defective phone

E(x) = n*p = 500 * 0.02 = 10

The average number of defective phones is 10.

b)Probability of getting 5 defective phones.

P(X=5) =

=

= 0.037

The probability of getting exactly 5 defective is 0.037.

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

here is a big fat