Reggie and alvin and jose are member of a relay running team reggie finish his leg of the race 2.4 five seconds faster than alvin and 3.8 one seconds slower than jose. if reggie time for his leg of the race was 57.12 seconds what was the total time for the team show your work

The time taken by Reggie for his leg of the race is 57.12 seconds.

Alvin is 2.45 seconds slower than Reggie. Therefore, time taken by Alvin for his leg of the race is:

seconds

We also know that Jose is faster than Reggie by 3.81 seconds. Therefore, time taken by Jose for his leg of the race will be:

seconds

Thus, the total time for the team will be the sum of the times taken by Reggie, Alvin and Jose for their respective legs.

Therefore, total time for the team is: seconds

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

75%

step-by-step explanation: