Suppose ms. kraus is 1.75 m tall. when her shadow is is 1 m, how long would the shadow be of a 265 m tall building? (make a sketch to solve the problem)

To solve the problem shown above you must apply the proccedure shown above:

 1. By using similar triangles, you can draw the diagram shown in the figure attached. Then, you have:

 1.75/265=1/x

 2. When you clear "x", you obtain:

 1.75x/265=1
 1.75x=(1)(265)
 x=265/1.75

 3. Therefore, you have that the result is:

 x=151.42 m

 How long would the shadow be of a 265 m tall building?

 As you can see, the answer is: 151.42 m

200 miles.45 x 3 (charge per day times days)135$205$ - 135$ = 70$0.35x = 70divide both sides by 0.35200