Arectangle is 4 cm longer than it is wide and its area is 117 cm². find its length. question 22 options: 4 cm 13 cm 9 cm 5 cm

Let
x---------> length side of rectangle
y--------> width side of rectangle

we know that
area of rectangle=x*y-----> 117 cm²-------> x*y=117-------> equation 1
x=4+y-------> equation 2
substitute 2 in 1

(4+y)*y=117-----> y²+4y-117=0

using a graph tool------> to resolve the second order equation
see the attached figure

y=9 cm
x=4+y-----> x=4+9-----> x=13 cm

the answer is
the length side of rectangle is 13 cm

6(2x + 5y)6 (2x) = 12x6 (5y) = 30y12x + 30y