Atriangular prism and two nets are shown: a right triangular prism is shown with two nets. the triangular base of the prism has height 5 inches, base 12 inches, and hypotenuse 13 inches. the length of the prism is 15 inches. net a has 3 rectangles having dimensions 5 by 15, 15 by 12, and 15 by 13, and two triangles having legs 5 inches and 12 inches. net b has 3 rectangles having dimensions 5 by 13, 13 by 12, and 13 by 15, and two triangles having legs 5 inches and 12 inches. which is the correct net of the prism and what is the surface area of the prism? a. net b with 420 square inches b. net b with 500 square inches c. net a with 510 square inches d. net a with 450 square inches

The answer is the option C

Net A with square inches

Step-by-step explanation:

we know that

The surface area is equal to the sum of the areas of all the faces

In this problem the correct Net is the figure A

To find the surface area find the area of the rectangles plus the area of the triangles

so

Find the area of the rectangles

Find the area of the triangles

Adds the areas

the answer is a

step-by-step explanation:

because your just changing the position of where the shape is

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: