The capulet and montague families love writing. last year, each capulet wrote 4 essays, each montague wrote 6 essays, and both families wrote 100 essays in total. this year, each capulet wrote 8 essays, each montague wrote 12 essays, and both families wrote 200 essays in total. how many capulets and montagues are there?

Infinite solution

Step-by-step explanation:

Let, number of Capulet family = x and number of Montague family = y.

Since, last year, each Capulet wrote 4 essays and each Montague wrote 6 essays.

Moreover, total essays wrote last year are 100.

So, we get, 4x + 6y = 100.

Again, this year, each Capulet wrote 8 essays and each Montague wrote 12 essays.

Moreover, total essays wrote this year are 200.

So, we get, 8x + 12y = 200.

Thus, the system of equations is given by,

4x + 6y = 100.

8x + 12y = 200.

Dividing first equation by 2 and second equation by 4, we get the equation,

2x + 3y = 50.

Since, there is only one equation and two variables i.e. x and y.

There can be infinite number of possibilities for the values of x and y.

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.