Evaluate the function for the indicated values of x. function f(−10) = f(2) = f(−5) = f(−1) = f(8) =

f(−10)

To find f(-10) we choose a function that has x value -10

-10 <= -5 so we use f(x) = 2x + 1

Plug in -10 for x

f(-10) = 2(-10) +1 = -20 +1 = -19 So f(-10) = -19

Now find f(2)

2 lies between -5 and 5 so we use f(x) = x^2

f(x)

f(2) = 4 . so f(2) = 4

f(−5)

-5 is equal to -5 so we use f(x) = 2x + 1

f(-5) = 2(-5) + 1 = -10 + 1 = -9

So f(-5) = -9

f(−1)

-1 lies between -5 and 5 so we use f(x)=

f(-1)= = 1 so f(-1) = 1

f(8)

8 is greater than 5 so we use f(x) = 3 - x

f(8) = 3 - 8 = -5 so f(8) = -5

Evaluating the piecewise function using the appropriate function based on the given value of x ; the values of f(x) are :

1.)

For f(-10) ; x = - 10:

We use ;

f(x) = 2x + 1

f(-10) = 2(-10) + 1

f(-10) = - 20 + 1 = - 19

2.) For f(2) :

We use f(x) = x² ;

f(2) = 2² = 4

3.) for f(-5) :

We use f(x) = 2x + 1 ;

f(-5) = 2(-5) + 1

f(-5) = - 10 + 1 = - 9

4.) For f(-1) :

We use f(x) = x²

f(-1) = (-1)² = 1

5.) For f(8) :

We use f(x) = 3 - x

f(8) = 3 - 8 = - 5

Hence, the value of the given x values using the piecewise function.

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b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.