Which absolute value functions will be narrower than the parent function, f(x) = |x|? check all that apply. f(x) = |x| f(x) = |x – 2| f(x) = |x| + 3 f(x) = 2.9|x| f(x) = 1.2|x + 8| f(x) = 0.7|x| – 3.2

Given parent function is f(x)=|x|

Now we have to find which function from given choices will be narrower than the parent function.

Notice that adding or subtracting some number from the parenth function only shifts the graph up, down, left of right side.

But that will not make function narrorwer or broader.

So f(x) = |x – 2| and  f(x) = |x| + 3, can't be the answer.

Multiplying by some positive real number which is more than 1, makes function narrower.

Only f(x) = 2.9|x| from remaining choices fits that case.

Hence f(x) = 2.9|x| is the final answer.

f(x) = 1.2|x + 8|  will also make the function narrower but will shift the parent function too.

answer: idk

step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!