Find the measures of the numbered angles in each special parallelogram, #22

We know that

In a parallelogram
1) Opposite angles are equal
2) Consecutive angles are supplementary
3)The diagonals of a parallelogram bisect each other
so
 problem N 21
see the attached figure to better understand the problem

∡A=2*32°----> ∡A=64°
∡A+∡B=180°-----> ∡B=180-64-----> ∡B=116°
∡1=∡B/2-----> ∡1=116°/2------> ∡1=58°

∡C=∡A
so
∡2=∡A/2-----> ∡2=32°
in the triangle BOC
∡BOC=90°
∡BOC +∡3=180--------> supplementary angles
∡3=180-90-----> ∡3=90°

the answers problem N 21 are
a) ∡1=58°
b) ∡2=32°
c) ∡3=90°

problem N 22  
see the attached figure to better understand the problem
∡1+56°=180°---------> supplementary angles
∡1=180-56---------> ∡1=124°

 triangle OBC (an isosceles triangle)
∡1+∡2+∡2=180--------> ∡2=(180-∡1)/2-----> ∡2=(180-124)/2---> ∡2=28°

∡2+∡3=90--------> complementary angles
∡3=90-∡2------> ∡3=90-28----> ∡3=62°

the answers problem N 22 are
a) ∡1=124°
b) ∡2=28°
c) ∡3=62°

Period is the time it takes for one “cycle” to complete. in the parent sine function, period is 2*pi since sin(0) = 0, sin(pi/2) = 1, sin(pi) = 0, sin(3pi/2) = -1, and sin(2pi) = 0. at that point, the sequence repeats itself. i’m not sure if your graph is similar to the sine function since you didn’t provide a picture, but you can find the period by looking at a graph.