Mariah is single and has a monthly disposable income of $3,200. her monthly cash outflow is approximately $2,800. mariah includes contributions to a retirement plan and money for investments as part of her cash outflow. she has car insurance and a life insurance policy. mariah has saved $15,000, but wishes to use $10,000 for a down payment on a house. she has also purchased furnishings for a house, which she has in the spare bedroom of her apartment. mariah hires a financial planner to examine her money management, and he determines that her plan needs work. what part of mariah’s financial plan would he encourage her to work on and why? a. her plan for managing income. her net cash flow is negative. b. her plan for managing her liquidity. she is spending all of her savings on her down payment. c. her plan for retirement. she does not have a retirement plan set up. d. her plan for protecting her assets. in case of an emergency, she should have renters insurance for her apartment.

The answer to the following question is...

d.

Her plan for protecting her assets. In case of an emergency, she should have renters insurance for her apartment.

Option D is correct.

Step-by-step explanation:

d. Her plan for protecting her assets. In case of an emergency, she should have renters insurance for her apartment.

This is because the house for which she is using almost 70% of her savings will become her asset after purchasing it. So, in case of emergencies, shw should not loose her assets and she should have renters insurance for her apartment.

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!