Create a factorable polynomial with a gcf of 2. rewrite that polynomial in two other equivalent forms. explain how each form was created.

Start with (x + 1)(x + 2).
We multiply the binomials to get:
x^2 + 2x + x + 2 = x^2 + 3x + 2
We know the polynomial x^2 + 3x + 2 is factorable because we created it by multiplying two binomials together.
Since we want to have a GCF of 2, we now multiply our polynomial by 2.
2(x^2 + 3x + 2) = 2x^2 + 6x + 4

We know that it factors into
2(x + 1)(x + 2)

If we combine the 2 with the first binomial, we get
(2x + 2)(x + 2)

If we combine the 2 with the right binomial we get
(x + 1)(2x + 4)

Therefore,
2x^2 + 6x + 4 = (2x + 2)(x + 2) = (x + 1)(2x + 4)

Xis equal to three