Aship leaves port at 1: 00 p. m. and travels s35°e at the rate of 27 mi/hr. another ship leaves the same port at 1: 30 p. m. and travels s20°w at 18 mi/hr. approximately how far apart are the ships at 3: 00 p. m.? (round your answer to the nearest mile.)

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at in for two hours. Therefore, the side is:

- The second ship travels at for . Therefore, the side is:

- Now, you can calculate :

The answer is:

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step-by-step explanation:

9-15%

the answer is b.)

< 1=< 2