Rewrite the equation of the circle (x-2)^2+y^2=3 in general form. a) x^2+y^2-4x+1=0 b)x^2+y^2-2x+7=0 c)x^2+y^2-2x+1=0 d) x^2+y^2-4x+7=0

y + 11 = (1/4)(x + 16)

step-by-step explanation:

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).