How many roots does the polynomial function y=(x-8)(x+3)^2 have

2

Step-by-step explanation:

the given polynomial has two roots

Step-by-step explanation:

the polynomial function y=(x-8)(x+3)^2

To find the number of roots we look at the exponent of each factor

(x-8) has exponent 1 ,   x=8 is a root (one root)

(x+3)^2 has exponent 2 , x=-3 is one of the root

(x+3)^2=0

take square root on both sides

x+3=0

x= -3

So the given polynomial has two roots 8 and -3

m∠abd = m∠dbc

step-by-step explanation:

given : ab bisects ∠dbc

as we know that bisection means ab divides   ∠dbc   in two equal angles named as   ∠dba and   ∠abc

so, m∠abd = m∠dbc  

because ab bisects ∠dbc.

hence , the first statement m∠abd = m∠dbc is true.