Given: abcd is a trapezoid, ab = cd, bk ⊥ ad, ak = 10, kd = 20 find: bc ad

BC = 10 and AD = 30

Step-by-step explanation:

In figure-1 , AB = CD ,BK ⊥ AD,  AK = 10,  KD = 20.

Since, line AD is sum of AK and  KD, then

AD = AK + KD

AD = 10 + 20

AD = 30

Since, BC ║AD and BK ⊥ AD then similarly we construct CL ⊥ AD

so, BC = KL and AK = LD

KL = AD - LD

KL = 20 - 10

KL = 10

Since, BC = KL then BC = 10

Hence, BC = 10 and AD = 30

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step-by-step explanation:

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