Quadrilateral abcd is located at a(−2, 2), b(−2, 4), c(2, 4), and d(2, 2). the quadrilateral is then transformed using the rule (x − 2, y + 8) to form the image a'b'c'd'. what are the new coordinates of a', b', c', and d'? describe what characteristics you would find if the corresponding vertices were connected with line segments.

Given vertices of the Quadrilateral ABCD :

A(−2, 2),

B(−2, 4),

C(2, 4), and

D(2, 2).

The quadrilateral is then transformed using the rule (x − 2, y + 8).

Let us find the coordinate  A', B', C', and D' by rule (x − 2, y + 8).

A(−2, 2) ---> (-2-2 , 2+8) = (-4, 10)

B(−2, 4) ---> (-2-2, 4+8) = (-4, 12)

C(2, 4), ---> ( 2-2, 4+8) = (0, 12)

D(2, 2) ---> (2-2, 2+8) = (0, 10).

So, the coordinates of A', B', C', and D' are

A'(-4, 10), B'(-4, 12), C'(0, 12), and D'(0, 10).

For the new coordinates we get we can say that each of the coordinate A', B', C', and D' moved 2 unit left and 8 units up.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.