Amir wants to show that tan3θ = (3tanθ-tan^3θ)/(1-3tan^2θ). he says he should use the double angle formula for the tangent function to do this. is he correct? a. yes he can write tan 3θ= tan 2(3/2 θ) and use the double angle formula b. yes he can write tan 3θ=(2θ+θ) and use the sum formula followed by the double angle formula c. no. because 3 is not a multiple of 2, he will have a 3/2 θ term that cannot be simplified d. no. because tan 2θ=(2tanθ)/(1-tan^2θ) there is no way to multiply the denominator by 3 to obtain 1-3tan^2θ

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

may i see the picture? it would a lot, xox