Atree that is 10 yards tall and casts a shadow 14 yards long. find the angle of elevation from the tip of the shadow to the top of the tree. round to the nearest degree -54 degrees - 36 degrees - 46 degrees - 44 degrees

36 degrees

Step-by-step explanation:

Refer the attached figure .

Height of tree i.e. AB = 10 yards

Length of shadow i.e. BC = 14 yards .

We are required to find the angle of elevation from the tip of the shadow to the top of the tree. i.e. ∠ACB

Now, we will use trigonometric ratio.

Thus the angle of elevation is 35.52° ≈ 36°

Hence  the angle of elevation from the tip of the shadow o the top of the tree. i.e. ∠ACB  is 36°

a box 3 3/4 feet long or 4+ feet.

step-by-step explanation: