3x-3y=-9 and 2x +y =9 solve for both x and y

You can solve for x and y by using the system of equations. That is when one term of one equation is opposite of its corresponding term in the other.

3x - 3y = -9
2x +  y = 9

You can get y to be the opposite of -3y by multiply the second equation by 3

3x - 3y = -9
6x + 3y = 27

Combine the equations, -3y and 3y cancel each other out

9x = 18
x = 2

Now plug the value of x back into one of the original equations

3x - 3y = -9
3(2) - 3y = -9
6 - 3y = - 9
-3y = -15
y = 5

To check you can plug both values into the other equation
2x + y = 9
4 + 5 = 9

Final x = 2, y = 5
Hope this helps!

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12