What is the vertex and y-intercept of f(x) = -2x^2 + 4x + 6

F(x)= -2x^2+4x+6
We can use -b/2a to find the line of symmetry
a= -2
b= 4
c= 6

and the x value for the line of symmetry gives you the x value for the vertex
-4/(2*-2)
-1=x

Plug this x value back into the function to find the y value for the vertex

f(x)= -2(-1)^2+(4*-1)+6
f(x)= -2+(-4)+6
f(x)= 0
the c value is the y intercept

Vertex: (-1,0)
Y intercept: 6

What’s your question.

Its d so thats how it would would back from 1.0 form three four two