What is the interquartile range for the data set? 89, 91, 95, 112, 118, 83, 85, 104, 118, 125, 134, 138 enter your answer in the box.

1. First, put the range in order and then divide the set into quarters. In this case, quartiles are between numbers.83, 85, 89,   l    91, 95, 104,  l   112, 118, 118,  l  125, 134, 138Q₁ = (89 + 91)/2 = 90Q₂ = (104 + 112)/2 =108Q₃ = (118 + 125)/2 = 121.5Interquartile range (IQR) = Q₃ - Q₁                                        = 121.5 - 90                                 IQR = 31.52. To find the standard deviation follow the simple steps.Formula in finding the standard deviation: (see attached file)     Step 1. Work out the simple average of the numbers (mean)                212 + 249 + 212 + 248 + 239 + 212 + 216 + 234 + 248                                                 9              = 2070                     9mean (μ) = 230        Step 2. Subtract the mean on each number and square the result.212 - 230 = (-18)² = 324249 - 230 = ( 19)² = 361212 - 230 = (-18)² = 324248 - 230 = (18)²  = 324239 - 230 = (9)²    = 81212 - 230 = (-18)² =324216 - 230 = (-14)² =196234 - 230 = (4)²    =16248 - 230 = (18)²  =324
     Step 3. Add all the squared results and get the mean.                  2274                     9       Variance = 252.6666667    Step 4. Get the square root of the variance.                  √252.6666667                  = 15.89549202